Integrand size = 11, antiderivative size = 122 \[ \int \frac {(a+b x)^{10}}{x} \, dx=10 a^9 b x+\frac {45}{2} a^8 b^2 x^2+40 a^7 b^3 x^3+\frac {105}{2} a^6 b^4 x^4+\frac {252}{5} a^5 b^5 x^5+35 a^4 b^6 x^6+\frac {120}{7} a^3 b^7 x^7+\frac {45}{8} a^2 b^8 x^8+\frac {10}{9} a b^9 x^9+\frac {b^{10} x^{10}}{10}+a^{10} \log (x) \]
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Time = 0.03 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int \frac {(a+b x)^{10}}{x} \, dx=a^{10} \log (x)+10 a^9 b x+\frac {45}{2} a^8 b^2 x^2+40 a^7 b^3 x^3+\frac {105}{2} a^6 b^4 x^4+\frac {252}{5} a^5 b^5 x^5+35 a^4 b^6 x^6+\frac {120}{7} a^3 b^7 x^7+\frac {45}{8} a^2 b^8 x^8+\frac {10}{9} a b^9 x^9+\frac {b^{10} x^{10}}{10} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (10 a^9 b+\frac {a^{10}}{x}+45 a^8 b^2 x+120 a^7 b^3 x^2+210 a^6 b^4 x^3+252 a^5 b^5 x^4+210 a^4 b^6 x^5+120 a^3 b^7 x^6+45 a^2 b^8 x^7+10 a b^9 x^8+b^{10} x^9\right ) \, dx \\ & = 10 a^9 b x+\frac {45}{2} a^8 b^2 x^2+40 a^7 b^3 x^3+\frac {105}{2} a^6 b^4 x^4+\frac {252}{5} a^5 b^5 x^5+35 a^4 b^6 x^6+\frac {120}{7} a^3 b^7 x^7+\frac {45}{8} a^2 b^8 x^8+\frac {10}{9} a b^9 x^9+\frac {b^{10} x^{10}}{10}+a^{10} \log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x)^{10}}{x} \, dx=10 a^9 b x+\frac {45}{2} a^8 b^2 x^2+40 a^7 b^3 x^3+\frac {105}{2} a^6 b^4 x^4+\frac {252}{5} a^5 b^5 x^5+35 a^4 b^6 x^6+\frac {120}{7} a^3 b^7 x^7+\frac {45}{8} a^2 b^8 x^8+\frac {10}{9} a b^9 x^9+\frac {b^{10} x^{10}}{10}+a^{10} \log (x) \]
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Time = 0.23 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.89
method | result | size |
default | \(10 a^{9} b x +\frac {45 a^{8} b^{2} x^{2}}{2}+40 a^{7} b^{3} x^{3}+\frac {105 a^{6} b^{4} x^{4}}{2}+\frac {252 a^{5} b^{5} x^{5}}{5}+35 a^{4} b^{6} x^{6}+\frac {120 a^{3} b^{7} x^{7}}{7}+\frac {45 a^{2} b^{8} x^{8}}{8}+\frac {10 a \,b^{9} x^{9}}{9}+\frac {b^{10} x^{10}}{10}+a^{10} \ln \left (x \right )\) | \(109\) |
norman | \(10 a^{9} b x +\frac {45 a^{8} b^{2} x^{2}}{2}+40 a^{7} b^{3} x^{3}+\frac {105 a^{6} b^{4} x^{4}}{2}+\frac {252 a^{5} b^{5} x^{5}}{5}+35 a^{4} b^{6} x^{6}+\frac {120 a^{3} b^{7} x^{7}}{7}+\frac {45 a^{2} b^{8} x^{8}}{8}+\frac {10 a \,b^{9} x^{9}}{9}+\frac {b^{10} x^{10}}{10}+a^{10} \ln \left (x \right )\) | \(109\) |
risch | \(10 a^{9} b x +\frac {45 a^{8} b^{2} x^{2}}{2}+40 a^{7} b^{3} x^{3}+\frac {105 a^{6} b^{4} x^{4}}{2}+\frac {252 a^{5} b^{5} x^{5}}{5}+35 a^{4} b^{6} x^{6}+\frac {120 a^{3} b^{7} x^{7}}{7}+\frac {45 a^{2} b^{8} x^{8}}{8}+\frac {10 a \,b^{9} x^{9}}{9}+\frac {b^{10} x^{10}}{10}+a^{10} \ln \left (x \right )\) | \(109\) |
parallelrisch | \(10 a^{9} b x +\frac {45 a^{8} b^{2} x^{2}}{2}+40 a^{7} b^{3} x^{3}+\frac {105 a^{6} b^{4} x^{4}}{2}+\frac {252 a^{5} b^{5} x^{5}}{5}+35 a^{4} b^{6} x^{6}+\frac {120 a^{3} b^{7} x^{7}}{7}+\frac {45 a^{2} b^{8} x^{8}}{8}+\frac {10 a \,b^{9} x^{9}}{9}+\frac {b^{10} x^{10}}{10}+a^{10} \ln \left (x \right )\) | \(109\) |
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Time = 0.21 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.89 \[ \int \frac {(a+b x)^{10}}{x} \, dx=\frac {1}{10} \, b^{10} x^{10} + \frac {10}{9} \, a b^{9} x^{9} + \frac {45}{8} \, a^{2} b^{8} x^{8} + \frac {120}{7} \, a^{3} b^{7} x^{7} + 35 \, a^{4} b^{6} x^{6} + \frac {252}{5} \, a^{5} b^{5} x^{5} + \frac {105}{2} \, a^{6} b^{4} x^{4} + 40 \, a^{7} b^{3} x^{3} + \frac {45}{2} \, a^{8} b^{2} x^{2} + 10 \, a^{9} b x + a^{10} \log \left (x\right ) \]
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Time = 0.08 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.03 \[ \int \frac {(a+b x)^{10}}{x} \, dx=a^{10} \log {\left (x \right )} + 10 a^{9} b x + \frac {45 a^{8} b^{2} x^{2}}{2} + 40 a^{7} b^{3} x^{3} + \frac {105 a^{6} b^{4} x^{4}}{2} + \frac {252 a^{5} b^{5} x^{5}}{5} + 35 a^{4} b^{6} x^{6} + \frac {120 a^{3} b^{7} x^{7}}{7} + \frac {45 a^{2} b^{8} x^{8}}{8} + \frac {10 a b^{9} x^{9}}{9} + \frac {b^{10} x^{10}}{10} \]
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Time = 0.21 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.89 \[ \int \frac {(a+b x)^{10}}{x} \, dx=\frac {1}{10} \, b^{10} x^{10} + \frac {10}{9} \, a b^{9} x^{9} + \frac {45}{8} \, a^{2} b^{8} x^{8} + \frac {120}{7} \, a^{3} b^{7} x^{7} + 35 \, a^{4} b^{6} x^{6} + \frac {252}{5} \, a^{5} b^{5} x^{5} + \frac {105}{2} \, a^{6} b^{4} x^{4} + 40 \, a^{7} b^{3} x^{3} + \frac {45}{2} \, a^{8} b^{2} x^{2} + 10 \, a^{9} b x + a^{10} \log \left (x\right ) \]
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Time = 0.29 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.89 \[ \int \frac {(a+b x)^{10}}{x} \, dx=\frac {1}{10} \, b^{10} x^{10} + \frac {10}{9} \, a b^{9} x^{9} + \frac {45}{8} \, a^{2} b^{8} x^{8} + \frac {120}{7} \, a^{3} b^{7} x^{7} + 35 \, a^{4} b^{6} x^{6} + \frac {252}{5} \, a^{5} b^{5} x^{5} + \frac {105}{2} \, a^{6} b^{4} x^{4} + 40 \, a^{7} b^{3} x^{3} + \frac {45}{2} \, a^{8} b^{2} x^{2} + 10 \, a^{9} b x + a^{10} \log \left ({\left | x \right |}\right ) \]
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Time = 0.05 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.89 \[ \int \frac {(a+b x)^{10}}{x} \, dx=a^{10}\,\ln \left (x\right )+\frac {b^{10}\,x^{10}}{10}+\frac {10\,a\,b^9\,x^9}{9}+\frac {45\,a^8\,b^2\,x^2}{2}+40\,a^7\,b^3\,x^3+\frac {105\,a^6\,b^4\,x^4}{2}+\frac {252\,a^5\,b^5\,x^5}{5}+35\,a^4\,b^6\,x^6+\frac {120\,a^3\,b^7\,x^7}{7}+\frac {45\,a^2\,b^8\,x^8}{8}+10\,a^9\,b\,x \]
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